Sequences+and+Series++Pythagorean+Theorem

=PYTHAGOREAN THEOREM   __Pythagorean Theorem__-A given right triangle in which C is the length of the hypotneuse and A and B represent the lenghts of its other two sides [|www.laredo.edu] __Area__-The number of square units needed to cover a surface [|www.laredo.edu] __Right Triangle__-a triangle containing an angle 90 [|www.laredo.edu] __Hypotneuse__-The side of the triangle that is opposite the right angle [|www.laredo.edu] __Legs(side__)-part of the triangle [|www.laredo.edu]  Pythagorean Theorem can be used in alot of things in the real world applications. You can use it in __construction,science, math__ ETC. Pythagorean Theorem is used in algebra. under this is a right triangle..  Pythagorean Theorem Equation=A^2+B^2=C^2     <span style="DISPLAY: block; FONT-SIZE: 70%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left"> = <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left"> <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left"> <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left">THE LEFT SIDE=A AND HYPOTENUSE=B <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left"> <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left"> <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left">Examples: <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left"> <span style="DISPLAY: block; FONT-SIZE: 150%; COLOR: #af00ff; FONT-FAMILY: 'Comic Sans MS', cursive; BACKGROUND-COLOR: #ffffff; TEXT-ALIGN: left">1. 12^2+B^2=20^2 144+B^2=400 B^2=256 2.2^2+3^2=C^2 4+9=C^2 (PRETTY EASY HUH?)

FIND THE EXACT DISTANCE BETWEEN EACH PAIR OF POINTS. THEN FIND THE MIDPOINT OF THE LINE SEGMENT WITH THE GIVEN POINTS. 3.(1,-2) AND (5,7) D=(1-5)^2+(-2-7)^2 =16+81 =97 YOU HAVE THE X,Y AXIS WHICH WAS (1,-2) AND (5,7).SO YOU SUBTRACT THE X AXIS FROM THE OTHER X AXIS AND THE Y FROM THE Y AXIS AND MAKE SURE EACH IS SQUARED. AND YOU SUBTRACT AND YOU GET 16+81 AND YOU SQUARE THAT ANSWER.

4.(3,5) AND (12,17) D=(3-12)^2+(5-17)^2 =81+144 =225 YOU BASICLY DO WHAT YOU DID WITH THE ONE U DID BEFORE.

LETS TRY A WORD PROBLEM. ONE LEG OF A RIGHT TRIANGLE IS 2 INCHES LONGER THAN THE OTHER LEG. IF THE HYPOTNEUSE IS 4 INCHES LONGER THAN THE SHORTEST LEG, FIND THE LENGTHS OF ALL THREE SIDES. USE PYTHAGOREAN THEOREM(A^2+B^2=C) X^2+(x+2)^2=2(x+4)2 x2+x2-4x-4+x^2+8x+16 x2-4x-12=0 (x-6)(x+2)=0 x=6 6,8,10

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